Skip to main content

Selina Concise Mathematics Class 6 ICSE Solutions – Fundamental Operations

Selina Concise Mathematics Class 6 ICSE Solutions – Fundamental Operations

Selina Concise Mathematics Class 6 ICSE Solutions – Fundamental Operations (Related to Algebraic Expressions)


IMPORTANT POINTS
1. Fundamental Operations : In mathematics, the operations : addition (+), subtraction (-), multiplication (x) and division (÷) are called the four fundamental operations.
2. Addition and Subtraction : 
o Addition of Like Terms : 
When all the terms are positive, add their coefficients.
When all the terms are negative, add their coefficients without considering their negative signs and then prefix the minus sign to the sum.
o Addition of Unlike Terms : As discussed above, the sum of two or more like terms is a single like term ; but the two unlike terms cannot be added together to get a single term.
o Subtraction of Like Terms : The same rules, as those for subtraction of integers, are applied for the subraction of like terms. The result of subtraction of two like terms is also a like term.
Add the positive terms together and negative terms separately together. Then, find the result of two terms obtained.

EXERCISE 19(A)
Question 1.
Fill in the blanks :
(i) 5 + 4 = ………… and 5x + 4x = ………….
(ii) 12 + 18 = ………… and 12x2y + 18x2y = ………….
(iii) 7 + 16 = ………….. and 7a + 16b = …………
(iv) 1 + 3 = ………… and x2y + 3xy2 = ………..
(v) 7 – 4 = …………… and 7ab – 4ab = …………..
(vi) 12 – 5 = ………… and 12x – 5y = ……………
(vii) 35 – 16 = ………….. and 35ab – 16ba = ………….
(viii) 28 – 13 = …………. and 28ax2 – 13a2x = ………….
Solution:
(i) 5 + 4 = 9 and 5x + 4x = 9x
(ii) 12 + 18 = 30 and 12x2y + 18x2y = 30x2y
(iii) 7 + 16 = 23 and 7a + 16 b = 7a + 16b
(iv) 1 + 3 = 4 and x2y + 3xy2 = x2y + 3xy2
(v) 7 – 4 = 3 and 7ab – 4ab = 3ab
(vi) 12 – 5 = 7 and 12x – 5y = 12x – 5y
(vii) 35 – 16 = 19 and 35ab – 16ba = 19ab
(viii) 28 – 13 = 15 and 28ax2 – 13a2x = 28ax2 – 13a2x

Question 2.
Fill in the blanks :
(i) The sum of – 2 and – 5 = …………. and the sum of – 2x and – 5x = …………….
(ii) The sum of 8 and – 3 = ………….. and the sum of 8ab and – 3ab = ………….
(iii) The sum of – 15 and – 4 = …………….. and the sum of – 15x and -4y = ………………
(iv) 15 + 8 + 3 = ……….. and 15x + 8y + 3x = …………….
(v) 12 – 9 + 15 = …………… and 12ab – 9ab + 15ba = ……………..
(vi) 25 – 7 – 9 = and 25xy – 7xy – 9yx = ……………
(vii) – 4 – 6 – 5 = …………. and – 4ax – 6ax – 5ay = …………….
Solution:
(i) The sum of – 2 and – 5 = – 7 and the sum of – 2x and – 5x = -7x
(ii) The sum of 8 and -3 = 5 and the sum of 8ab and – 3ab = 5ab
(iii) The sum of – 15 and – 4 = – 19 and the sum of – 15x and – 4y = – 15x – 4y
(iv) 15 + 8 + 3 = 26 and 15x + 8y + 3x = 18x + 8y
(v) 12 – 9 + 15 = 18 and 12ab – 9ab + 15ba = 18ab
(vi) 25 – 7 – 9 = 9 and 25xy – 7xy – 9yx = 9xy
(vii) – 4 – 6 – 5 = – 15 and – 4ax – 6ax – 5ay = – 10ax – 5ay

Question 3.
Add:
(i) 8xy and 3xy
(ii) 2xyz, xyz and 6xyz
(iii) 2a, 3a and 4b
(iv) 3x and 2y
(v) 5m, 3n and 4p
(vi) 6a, 3a and 9ab
(vii) 3p, 4q and 9q
(viii) 5ab, 4ba and 6b
(ix) 50pq, 30pq and 10pr
(x) – 2y, – y and – 3y
(xi) – 3b and – b
(xii) 5b, – 4b and – 10b
(xiii) – 2c, – c and – 5c
Solution:
(i) 8xy + 3xy = 11xy
(ii) 2xyz + xyz + 6xyz = (2 + 1 + 6) xyz = 9xyz
 
 
Question 4.
Evaluate :
 
Solution:
(i) 6a – a – 5a – 2a = 6a – (1 + 5 + 2).a
 
Question 5.
Evaluate :
 
Solution:
 
Question 6.
Subtract the first term from the second :
 
Solution:
 
Question 7.
Simplify :
 
 
Solution:
 
 
 
 
EXERCISE 19(B)
Question 1.
Find the sum of :
 
Solution:
 
 
 
Question 2.
Add the following expressions :
 
 
Solution:
 
Question 3.
Evaluate :
 
Solution:
 
 
Question 4.
Subtract :
 
Solution:
 
 
Question 5.
 
Solution:
 
Question 6.
From the sum of x + y – 2z and 2x – y + z subtract x + y + z.
Solution:
 
Question 7.
From the sum of 3a – 2b + 4c and 3b – 2c subtract a – b – c.
Solution:
 
Question 8.
Subtract x – 2y – z from the sum of 3x – y + z and x + y – 3z.
Solution:
(3x – y + z) + (x + y – 3 z) – (x – 2y – z)
= 3x – y + z + x + y – 3z – x + 2y + z
= 3x + x – x – y + y + 2y + z + z – 3z
= 3x + 2y – z

Question 9.
Subtract the sum of x + y and x – z from the sum of x – 2z and x + y + z
Solution:
 
Question 10.
By how much should x + 2y – 3z be increased to get 3x ?
Solution:
3x – (x + 2y – 3z)
= 3x – x – 2y + 3z
= 2x – 2y + 3z

Question 11.
The sum of two expressions is 5x2 – 3y2. If one of them is 3x2 + 4xy – y2, find the other.
Solution:
 
Question 12.
The sum of two expressions is 3a2 + 2ab – b2. If one of them is 2a2 + 3b2, find the other.
Solution:
 
EXERCISE 19(C)
Question 1.
Fill in the blanks :
 
Solution:
(i) 6 x 3 = 18 and 6x x 3x = 6 x 3x x x x = 18x2
 
Question 2.
Fill in the blanks :
 
Solution:
 
 
Question 3.
Find the value of :
 
Solution:
 
Question 4.
Multiply :
 
 
Solution:
 
Question 5.
Multiply :
 
Solution:
 
 
Question 6.
Multiply :
 
Solution:
 
Question 7.
Multiply :
(i) x + 2 and x + 10
(ii) x + 5 and x – 3
(iii) x – 5 and x + 3
(iv) x – 5 and x – 3
(v) 2x+ y and x+ 3y
(vi) (3x – 5y) and (x + 6y)
(vii) (x + 9y) and (x – 5y)
(viii) (2x + 5y) and (2x + 5y)
Solution:
 
 
Question 8.
Multiply :
 
Solution:
 
 
Question 9.
Find the product of :
 
Solution:
 
 
 
EXERCISE 19(D)
Question 1.
Divide :
 
Solution:
 
Question 2.
Simplify :
 
 
Solution:
 
 
Question 3.
Divide :
 
 
Solution:
 
 
Question 4.
Simplify :
 
Solution:
 
Question 5.
Divide :
 
 
Solution:
 

Comments

Popular posts from this blog

Selina Concise Physics Class 10 ICSE Solutions Chapter 12 - Radioactivity

Selina Concise Physics Class 10 ICSE Solutions Radioactivity Selina ICSE Solutions for Class 10 Physics Chapter 12 Radioactivity Exercise 12(A) Solution 1. Three constituent of an atom are: Electrons: mass is 9.1 x 10-31 kg, charge is -1.6 x 10-19C Neutron: mass is 1.6749 x 10-27 kg, charge is zero. Protons: mass is 1.6726 x 10-27 kg, charge is +1.6 x 10-19 C Solution 2 . Atomic number – the number of protons in the nucleus is called atomic number. Mass number – the total number of nucleons in the nucleus is called mass number. Solution 3. The nucleus at the centre of atom, whose size is of the order of 10-15 m to 10-14 m. The size of a nucleus is 10-5 to 10-4 times the size of an atom. It consists of protons and neutrons. If Z is the atomic number and A is the mass number of an atom, then the atom contains Z number of electrons; Z number of protons and A – Z number of neutrons. The atom is specified by the symbol ZXA where X is the chemical symbol for the element. Solution 4....

Selina Concise Physics Class 10 ICSE Solutions Chapter 4 - Refraction of Light at Plane Surfaces

Selina Concise Physics Class 10 ICSE Solutions Refraction of Light at Plane Surfaces Selina ICSE Solutions for Class 10 Physics Chapter 4 Refraction of Light at Plane Surfaces Exercise 4(A) Solution 1. The change in the direction of the path of light, when it passes from one transparent medium to another transparent medium, is called refraction of light . Solution 2.    Solution 3. The ray of light which is incident normally on a plane glass slab passes undeviated. That is such a ray suffers no bending at the surface because here the angle of incidence is 0°. Thus if angle of incidence ∠i = 0°, then the angle of refraction ∠r = 0°. And the angle of deviation of the ray will also be 0°. Solution 5. The refraction of light (or change in the direction of path of light in other medium) occurs because light travels with different speeds in different media. When a ray of light passes from one medium to another, its direction (except for ∠i = 0°) changes because of change in its spe...

ICSE Solutions for Class 9 History and Civics – Industrial Revolution and Capitalism and Socialism

ICSE Solutions for Class 9 History and Civics – Industrial Revolution and Capitalism and Socialism ICSE Solutions for Class 9 History and Civics – Industrial Revolution and Capitalism and Socialism EXERCISES Question 1. What is meant by Industrial Revolution? Answer: The word ‘Revolution means, something “sudden and quite swift”. Industrial Revolution resulted in revolutionary changes in all walks of life. Question 2. Mention any two causes responsible for Industrialisation in England. Answer: Reasons for the initiation of Industrialisation in England are: Enclosure Movement (Availability of Cheap Labour).  Availability of Coal and Iron. Question 3. What is a Capitalist system? Answer: A Capitalist system is the economic system in which business and industries were owned by private individuals and not by the State. Question 4. Mention the two main features of Capitalism. Ans. Under this system the productive wealth remains in private hands. Therefore, the owners of wealth have exc...